11y^2+10y-2=0

Solution for 11y^2+10y-2=0 equation:

11y^2+10y-2=0

a = 11; b = 10; c = -2;
Δ = b2-4ac
Δ = 102-4·11·(-2)
Δ = 188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{188}=\sqrt{4*47}=\sqrt{4}*\sqrt{47}=2\sqrt{47}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{47}}{2*11}=\frac{-10-2\sqrt{47}}{22}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{47}}{2*11}=\frac{-10+2\sqrt{47}}{22}
$